Answer:
Step-by-step explanation:
[tex]\frac{1}{2}-3(\frac{1}{2}+1)^{2} = \frac{1}{2}-3(\frac{1}{2}+\frac{1*2}{1*2} )^{2}[/tex]
[tex]=\frac{1}{2}-3(\frac{1}{2}+\frac{2}{2} )^{2}\\\\\\=\frac{1}{2}-3(\frac{3}{2})^{2}\\\\\\=\frac{1}{2}-3*\frac{9}{4}\\\\\\=\frac{1*2}{2*2}-\frac{27}{4}\\\\\\=\frac{2}{4}-\frac{27}{4}\\\\\\=\frac{2-27}{4}\\\\=\frac{-25}{4}\\\\\\= -6\frac{1}{4}[/tex]
