Answer:
A truck weighing 3.0 × 104
newtons was driven up a
hill that is 1.6 × 103
meters long to a level area that
is 8.0 × 102
meters above the starting point. If the
trip took 480 seconds, what was the minimum power
required?
Explanation:
the answer is 1292.8
brainliest plzzzzzzzzzzzzzzzzzzzzzz
Answer:
5.0x10^4
Explanation:
Im gunna geuss that you didn't add the exponents so...
P=power
F=force
d=displacment
P=Fd
equation:
3.0x10^4(1.6x10^3 - 8.0x10^2)/480
=30000(800)/480
=50000 or 5.0x10^4
