A study of 800 homeowners in a certain area showed that the average value of the homes was $82,000, and the standard deviation was $5000. How many of these homes have a value greater than $83,500.

Round to a whole number.
I got 62 it says that is wrong answer.

Respuesta :

Answer:

400

Step-by-step explanation:

it says average which probably means 400

33.36% of these homes have a value greater than $83,500.

The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

[tex]z=\frac{x-\mu}{\sigma} \\\\where\ x \ is\ raw\ score,\mu=mean,\sigma=standard\ deviation[/tex]

Given that μ = $82000, σ = $5000.

For x > 83500:

[tex]z=\frac{83500-82000}{5000} =0.43[/tex]

From the normal distribution table, P(x > 83500) = P(z > 0.43) = 1 - P(z < 0.43) = 1 - 0.6664 = 33.36%

33.36% of these homes have a value greater than $83,500.

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