We have that for the Question "Light travels in a transparent material at 2.5 x 10 m/s. Find the index of refraction of the material." it can be said that
From the question we are told
Light travels in a transparent material at 2.5 x 10 m/s. Find the index of refraction of the material.
Generally the equation for the index of refraction is mathematically given as
[tex]n=\frac{C}{v}\\\\Therefore\\\\n=\frac{3*10^8}{2.5 * 10 }\\\\n=12000000\\\\[/tex]
Therefore
The index of refraction of the material is
n=12000000
For more information on this visit
https://brainly.com/question/23379286
