In the figure shown, triangle RST undergoes reflections across two line. R''S''T’’ is the final image of RST

Triangle RST is first reflected across the line x=0 and then across line
a. x=0
b. y=0
c. y=x
d. y=-x

When we reflect it over the line x = 0, aka the y axis, we use the rule [tex](x,y) \to (-x,y)[/tex] so T(-2,1) becomes T ' (2, 1). The x coordinate flipped in sign, while the y coordinate stays the same.

Then the final transformation is reflecting over y = -x using the rule [tex](x,y) \to (-y, -x)[/tex]. Therefore, the point (2,1) moves to (-1, -2) which is where T'' is located in the diagram.

You apply the same two transformations for the points R and S to get R'' and S'' respectively.

Note: A composition of two reflections, where the lines of reflection aren't parallel, form a rotation. In this case, we have a 90 degree counterclockwise rotation when going from triangle RST to triangle R''S''T''.

In the figure shown, triangle RST undergoes reflections across two line. R''S''T’’ is the final image of RST Triangle RST is first reflected across the line x=0 and then across line a. x=0 b. y=0 c. y=x d. y=-x

Respuesta :

Answer: D. y = -x

Otras preguntas

In the figure shown, triangle RST undergoes reflections across two line. R''S''T’’ is the final image of RST

Triangle RST is first reflected across the line x=0 and then across line
a. x=0
b. y=0
c. y=x
d. y=-x