Answer:
The standard error of the mean is 0.02
Step-by-step explanation:
Here, we want to calculate the standard error of the mean.
Mathematically;
standard error of mean = SD/ √n
where SD is the standard deviation and n is the number of samples
From the question, SD = 0.22 and n = 121
Inserting this into the equation
Standard error of the mean = 0.22/√121
= 0.22/11 = 0.02
The probability of obtaining a sample mean is "0.9545".
According to the question,
Mean,
[tex]\mu = 4[/tex]
Standard deviation,
[tex]\sigma = 0.22[/tex]
Random sample,
[tex]n = 121[/tex]
By Central limit theorem,
→ [tex]\bar {x} \sim (4, \frac{0.22}{\sqrt{121} } )[/tex]
   [tex]= 0.2[/tex]
Now,
→ [tex]P(|\bar{x} - \mu| \ \alpha \ 0.04) = P(-0.04 \ \alpha \ \bar{x} - \mu \ \alpha \ 0.04)[/tex]
                [tex]= P(\frac{-0.04}{0.02} \ \alpha \ z \ \alpha \ \frac{0.04}{0.02} )[/tex]
                [tex]= P(-2 \ \alpha \ z \ \alpha \ 2)[/tex]
                [tex]= 0.9545[/tex]
Thus the above response i.e., "option a" is appropriate.
Learn more:
https://brainly.com/question/16943601
