In a game, you have a 1/21 probability of winning $107 and a 20/21 probability of losing $5. What is your expected winning?
A) $0.33
B) $9.86
C) $5.10
D) -$4.76

Respuesta :

Answer:

The correct option is A.

Step-by-step explanation:

The formula to compute the expected value is:

[tex]E(X)=\sum x\cdot P(X)[/tex]

The information provided can be summarized as follows:

              X         P (X)

Win     $107       1/21

Lose     -$5       20/21

Compute the value of expected winning as follows:

[tex]E(X)=\sum x\cdot P(X)[/tex]

          [tex]=(107\times\frac{1}{21})+(-5\times\frac{20}{21})\\\\=\frac{107}{21}-\frac{100}{21}\\\\=\frac{107-100}{21}\\\\=0.33333333\\\\\approx \$0.33[/tex]

Thus, the value of expected winning is $0.33.

The correct option is A.

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