The pH of the solution after the titration has been 1.318.
pH can be defined as the negative logarithmic values of the hydrogen ion concentration in the solution.
The remaining acid solution has been responsible for the pH of the solution.
The moles of acid can be given by:
Moles = Molarity × Volume
Moles of acetic acid = 0.1 M × 0.025 L
Moles of acetic acid = 0.0025 moles
Moles of NaOH = 0.1 M × 0.01 L
Moles of NaOH = 0.001 moles.
By the neutralization reaction, the moles of acid remaining has been:
Mole of acid remaining = Moles of acid - Moles of NaOH
Moles of acid remaining = 0.0025 - 0.001
Moles of acid remaining = 0.0015 moles.
The hydrogen ions liberated by the acetic acid have been equivalent to the moles of acetic acid.
Thus, the moles of hydrogen ions = 0.0015 mol.
The concentration of hydrogen ions has been:
Molarity = [tex]\rm \dfrac{moles}{volume\;(L)}[/tex]
Molarity of hydrogen ion = [tex]\rm \dfrac{0.0015}{0.025\;+\;0.01\lL}[/tex]
Molarity of the hydrogen ion has been = 0.0428 M.
The pH of the solution has been:
pH = -log [Hydrogen concentration]
pH = -log (0.0428)
pH = 1.318.
The pH of the solution after the titration has been 1.318.
For more information about the pH of titration, refer to the link:
https://brainly.com/question/9707819
