Answer:
a
The 95% confidence interval is [tex] 0.2474 < p < 0.3188 [/tex]
b
The result obtained does not contradict expectation
Step-by-step explanation:
From the question we are told that
The number of green peas is k = 438
The number of yellow peas is u = 173
Generally the sample size is mathematically represented as
[tex]n = k + u[/tex]
=> [tex]n = 438 + 173[/tex]
=> [tex]n = 611[/tex]
Generally the sample proportion for yellow peas is
[tex]\^ p = \frac{u}{n}[/tex]
=> [tex]\^ p = \frac{173}{611 }[/tex]
=> [tex]\^ p = 0.2831[/tex]
From the question we are told the confidence level is 95% , hence the level of significance is
[tex]\alpha = (100 - 95 ) \%[/tex]
=> [tex]\alpha = 0.05[/tex]
Generally from the normal distribution table the critical value of [tex]\frac{\alpha }{2}[/tex] is
[tex]Z_{\frac{\alpha }{2} } = 1.96[/tex]
Generally the margin of error is mathematically represented as
[tex]E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} } [/tex]
=> [tex]E = 1.96 * \sqrt{\frac{ 0.2831 (1- 0.2831)}{611} } [/tex]
=> [tex]E = 0.0357 [/tex]
Generally 95% confidence interval is mathematically represented as
[tex]\^ p -E < p < \^ p +E[/tex]
=> [tex] 0.2831 -0.0357 <p< 0.2831 + 0.0357[/tex]
=> [tex] 0.2474 < p < 0.3188 [/tex]
From the question we are told that it was expected that 25% of the offspring peas will be yellow
Now from the 95% confidence interval obtained we see that the expected sample proportion(25% ) falls within it so it means that the result obtained does not contradict expectation
