18% of all US residents have traveled to Canada, 9% to Mexico, and 4% to both. What is the probability that a US resident chosen at random has a. traveled to Canada or Mexico?

Respuesta :

Answer:

[tex]P(Canada\ or\ Mexico)= 23\%[/tex]

Step-by-step explanation:

Given

[tex]P(Canada) = 18\%[/tex]

[tex]P(Mexico) = 9\%[/tex]

[tex]P(Both) = 4\%[/tex]

Required

Determine [tex]P(Canada\ or\ Mexico)[/tex]

In probability:

[tex]P(A\ or\ B) = P(A) + P(B) - P(Both)[/tex]

In this case:

[tex]P(Canada\ or\ Mexico)= P(Canada) + P(Mexico) - P(Both)[/tex]

Substitute values:

[tex]P(Canada\ or\ Mexico)= 18\% + 9\% - 4\%[/tex]

[tex]P(Canada\ or\ Mexico)= 23\%[/tex]

Hence, the required probability is 23%

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