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What is the ideal banking angle for a gentle turn of 1.20-km radius on a highway with a 105 km/h speed limit (about 65 mi/h), assuming everyone travels at the limit?

Respuesta :

skpattylah

Answer:

4.14°

Explanation:

given:

r = 1.2 km

v = 105 km/h

1) convert your given

a) r = 1.2 km to m = 1200m

b) v = 105 km/h  to m/s = 29.2 m/s

2) plug into your ideal banking angle equation

[tex]tan^-1[/tex]([tex]\frac{v^2}{rg}[/tex]) = [tex]\frac{29.2^2}{(1200)(9.8)}[/tex] = 4.14°

pstnonsonjoku

Roads are banked to prevent toppling.

Given the following information from the question;

velocity of the cyclist(v) = 105 km/h or 29 m/s

radius of the turn(r) =  1.20-km or 1200 m

Acceleration due to gravity (g)= 10m/s^2

Using the formula;

θ = tan-1(v^2/rg)

θ =tan-1[ (29)^2/ 1200 × 10]

θ =4°

Learn more: https://brainly.com/question/2673886

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