If A is the area of a circle with radiusr and the circle expands as time passes, find dA/dt in terms of dr/dt.
So I have, A= π r2
dA/dt = 2π r (dr/dt)

Respuesta :

Answer:

[tex]\frac{dA}{dt} = 2\pi r(\frac{dr}{dt})[/tex]

Step-by-step explanation:

Your solution is correct (See explanation):

Area (A) of a circle is

[tex]A = \pi r^2[/tex]

Where

[tex]r = radius[/tex]

Differentiate both sides with respect to t

[tex]\frac{dA}{dt} = 2\pi r(\frac{dr}{dt})[/tex]

This is so because, we have to differentiate A on the left hand side and r on the right hand side because [tex]2\pi[/tex] is a constant

Hence, your solution is correct and and

[tex]\frac{dA}{dt} = 2\pi r(\frac{dr}{dt})[/tex]

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