PLEASE HURRY: Review the proof of sin(A – B) = sinAcosB – cosAsinB

sin(A – B) =

Step 1: Equals cosine left-bracket (StartFraction pi Over 2 EndFraction minus A) + B right-bracket

Step 2: Equals cosine left-bracket StartFraction pi Over 2 EndFraction minus (A minus B) right-bracket

Step 3: Equals cosine (StartFraction pi Over 2 EndFraction minus A) cosine B minus sine (StartFraction pi Over 2 EndFraction minus A) sine B

Step 4: = sinAcosB – cosAsinB

How must the proof be rearranged for the steps to logically follow each other?

a. Step 3 should be step 1.

b. Step 4 should be step 1.

c. Steps 1 and 2 must be switched.

d. Steps 1 and 3 must be switched.

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themountaintrolls themountaintrolls · Answer 1 · 2020-11-11T07:21:27+01:00

Answer:

C.) Steps 1 and 2 must be switched.

Step-by-step explanation:

correct on edge

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AFOKE88 AFOKE88 · Answer 2 · 2022-06-07T18:16:53+02:00

The way the proof must be rearranged for the steps to logically follow each other is; C: Step 1 and 2 must be switched.

We want to prove;

sin(A – B) = sinAcosB – cosAsinB

We are given the steps in the trigonometric proof as;

First Step = cos[(¹/₂π - (A - B]

Second Step = cos[(¹/₂π - A) + B]

Third Step = cos(¹/₂π - A) cos B - sin (¹/₂π - A) sin B

Fourth Step = sinAcosB – cosAsinB

Now, looking at the given steps, the first step will be;

cos[(¹/₂π - A) + B].

The reason that is the first step is that;

sin(A - B) = sin(A +(-B))

Thus, the first step has to be switched with the second step.

Read more about Trigonometric Identities at; https://brainly.com/question/7331447

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