Respuesta :
Answer:
[tex]P(4\ or\ 5) = 0.446[/tex]
Step-by-step explanation:
See attachment for complete question (histogram)
From the histogram, we have:
[tex]P(0) = 0.007[/tex]
[tex]P(1) = 0.049[/tex]
[tex]P(2) = 0.181[/tex]
[tex]P(3) = 0.317[/tex]
[tex]P(4) = 0.332[/tex]
[tex]P(5) = 0.114[/tex]
At least 4 of the next 5 means that: 4 or 5
Hence, the required probability means: P(4 or 5)
And it is calculated as:
[tex]P(4\ or\ 5) = P(4) + P(5)[/tex]
Substitute values for P(4) and P(5)
[tex]P(4\ or\ 5) = 0.332 + 0.114[/tex]
[tex]P(4\ or\ 5) = 0.446[/tex]
Hence, the required probability is 0.446
The probability that atleast four of the next 5 flight will be overbooked is the sum of the probabilities that either 4 or 5 of the flights will be overbooked which is 0.446
The probability that :
- 4 flights will be overbooked = P(4) = 0.332
- 5 flights will be overbooked = P(5) = 0.114
Probability that atleast 4 flights will be overbooked can be interpreted thus :
P(X ≥ 4) = P(4) + P(5)
P(X ≥ 4) = 0.332 + 0.114 = 0.446
Therefore, the probability that atleast 4 of the next 5 flights will be overbooked is 0.446
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