Respuesta :
Answer:
(a) The mass of camphor in 30 g of Flexible collodion = 6 g
The mass of castor oil in 30 g of Flexible collodion = 9 g
(b) 9.424 ml
(c) W/v concentration of Lactic acid in the mixture ≈ 3.12 %
W/v concentration of Salicylic acid in the mixture ≈ 3.9 %
W/v concentration of Trichloroacetic acid in the mixture ≈ 1.56 %
Explanation:
(a) The given parameters are;
The percentage of camphor in Flexible collodion = 20%
The percentage of castor oil in Flexible collodion = 30%
Therefore, we have;
The mass of camphor in 30 g of Flexible collodion = 20/100 × 30 g = 6 g
The mass of castor oil in 30 g of Flexible collodion = 30/100 × 30 g = 9 g
(b) The given specific gravity of castor oil = 0.955
Therefore, the ratio of the density of castor oil to the density of water = 0.955
The density of water ≈ 1 g/ml
Therefore, the density of castor oil ≈ 0.955 × 1 g/ml = 0.955 g/ml
Density = Mass/Volume
∴ Volume = Mass/Density
The volume of the 9 grams of castor oil in the mixture = 9 g/(0.955 g/ml) = 9.424 ml
c. Given that the specific gravity of the mixture = 0.781, and the volume
We have;
The density of the mixture ≈ 0.781 × 1 g/ml = 0.781 g/ml
Whereby the content of Flexible collodion, by weight, includes;
Mass of Lactic acid per 100 g = 4 g
Mass of Salicylic acid per 100 g = 5 g
Mass of Trichloroacetic acid per 100 g = 2 g
We have the volume of 100 g sample, = 100/0.781 ≈ 128.04 ml
Therefore; we have;
w/v concentration of Lactic acid in the mixture = 4/128.04×100 ≈ 3.12 %
w/v concentration of Salicylic acid in the mixture = 5/128.04×100 ≈ 3.9 %
w/v concentration of Trichloroacetic acid in the mixture = 2/128.04×100 ≈ 1.56 %.
The mass of each gram of camphor is 5 grams, and the mass of each gram of castor oil is 3.33 grams.
(a) The mass percentage has been the mass present in 100 grams of solution.
- The mass of camphor (20 % w/w)
100 grams solution = 20 grams camphor
1 gram solution = 5 grams camphor.
- The mass of Castor oil (30% w/w)
100 grams solution = 30 grams castor oil
1 gram solution = 3.33 grams castor oil.
(b) Specific gravity has been the ratio of the density of a compound with water.
The density of water has been approximately equal to 1.
The specific gravity = density of compound.
The specific gravity of castor oil = density of castor oil.
0.955 g/ml = density of castor oil.
Density has been the ratio of mass to volume.
Density = [tex]\rm \dfrac{mass}{volume}[/tex]
Mass of castor oil = 30 g.
Volume = [tex]\rm \dfrac{mass}{density}[/tex]
The volume of 30 grams castor oil = [tex]\rm \dfrac{30}{0.955}[/tex]
The volume of 30 grams castor oil = 31.413 ml.
(c) From the specific gravity, the density of solution = 0.781 g/ml
For 100 g solution, volume of solution = 128.04 ml
The given mass of lactic acid = 4 g
Salicylic acid = 5 g
Trichloroacetic acid = 2 grams.
The percent concentration of w/v has been given by:
Percent composition = [tex]\rm \dfrac{mass}{volume}\;\times\;100[/tex]
- Percent composition (w/v) Lactic acid = [tex]\rm \dfrac{4}{128.04}\;\times\;100[/tex]
Percent composition (w/v) Lactic acid = 3.124 %
- Percent composition (w/v) Salicylic acid = [tex]\rm \dfrac{5}{128.04}\;\times\;100[/tex]
Percent composition (w/v) Salicylic acid = 3.905 %
- Percent composition (w/v) Trichloroacetic acid = [tex]\rm \dfrac{2}{128.04}\;\times\;100[/tex]
Percent composition (w/v) Trichloroacetic acid = 1.562 %
For more information about percent composition, refer to the link:
https://brainly.com/question/17505281
