contestada

How many grams of propanol (C3H7OH, 60.10 g/mol) would be needed to make 750 mL of a solution with an osmotic pressure of 25 atm at 25°C? (R = 0.0821 L.atm/K.mol)

Respuesta :

adrianabazan
Answer:

= 46.06 grams

Explanation:

P=cRT

25 = c (0.0821)(298)

concentration = c = 1.021 M

number of moles = (1.021)(0.75) = 0.7664 moles

mass = (0.7664)(60.10)=40.06 grams

Otras preguntas

Q&A Education