The number of moles of chloride ions is in 0.2 L of a 0.5 molar AlCl3 solution should be 0.3 moles.
Since
the molarity of AlCL3 is 0.5m and the volume of the solution is 0.2 L.
So here the moles of AlCL3 should be
= 0.5 * 0.2
= 0.1 mole
Now the moles of chloride ions should be
= 3 *0.1 moles
= 0.3 moles
hence, The number of moles of chloride ions is in 0.2 L of a 0.5 molar AlCl3 solution should be 0.3 moles.
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