The slope of the line that passes through (-10, 0) and (-13, 3) is "-1".
Given points are:
- [tex](x_1, y_1) = (-10,0)[/tex]
- [tex](x_2,y_2) = (-13,3)[/tex]
As we know, the formula,
→ [tex]Slope (m) = \frac{y_2-y_1}{x_2-x_1}[/tex]
By substituting the above points, we get
→ [tex]= \frac{3-0}{-13-(-10)}[/tex]
→ [tex]= \frac{3}{-13+10}[/tex]
→ [tex]= \frac{3}{-3}[/tex]
→ [tex]= -1[/tex]
Thus the solution is right.
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