Answer:
Horizontal component of velocity = 241.61 m/s
Explanation:
Given that,
Velocity of a jetliner is 245 m/s
The vertical component of the plane's velocity is 40.6 m/s, [tex]v_y=40.6\ m/s[/tex]
We need to find the magnitude of the horizontal component of the plane velocity.
The resultant velocity is given by :
[tex]v=\sqrt{v_x^2+v_y^2}[/tex]
Where, [tex]v_x[/tex] is the horizontal component of the plane velocity
[tex]v^2=v_x^2+v_y^2\\\\v_x^2=v^2-v_y^2\\\\v_x^2=(245)^2-(40.6)^2\\\\v_x=\sqrt{58376.64}\\\\v_x=241.61\ m/s[/tex]
So, the magnitude of the horizontal component of the plane velocity is 241.61 m/s.
