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Shelby the Skater's rocket provides a forward force of
220 Newtons. Shelby has a mass of 60. kg. If friction
provides a resistive force of 30. Newtons, then at what
rate does Shelby accelerate? Show all work.

Respuesta :

Answer:

[tex]a=3.17\ m/s^2[/tex]

Explanation:

Given that,

Force force acting on the Skater's rocket is 220 N

Resistive force acting on it, F' = 30 N

Mass of Shelby, m = 60 kg

We need to find the acceleration of Shelby. Net force acting on Shelby is given by :

Net force = 220-30

= 190 N

The formula of net force is :

F = ma

a is acceleration of Shelby

[tex]a=\dfrac{F}{m}\\\\a=\dfrac{190}{60}\\\\a=3.17\ m/s^2[/tex]

So, the acceleration of Shelby is [tex]3.17\ m/s^2[/tex]

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