Na2SO3 + 2 AlCl3 --> Al2(SO3)3 + 6 NaCl Using the above reaction, suppose (1.760x10^2) grams of Na2SO3 were added to (6.5x10^1) grams of AlCl3, how much (in g) of NaCl was produced once the reaction was run to completion?

Respuesta :

Mass NaCl produced : 171.81 g

Further explanation

The reaction equation is the chemical formula of reagents and product substances  

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products  

Na₂SO₃ : 176 g

MW : 126,043 g/mol

mol :

[tex]\tt \dfrac{176}{126.043}=1.4[/tex]

AlCl₃ : 65 g

MW : 133,34 g/mol

mol :

[tex]\tt \dfrac{65}{133.34}=0.49[/tex]

Reaction

Na₂SO₃ + 2 AlCl₃ ⇒ Al₂(SO₃)₃ + 6NaCl

limiting reactants:

mol ratio(mol/coefficient) Na₂SO₃ : 2 AlCl₃ =

[tex]\tt \dfrac{1.4}{1}:\dfrac{0.49}{2}=1.4:0.245[/tex]

AlCl₃ ⇒ limiting reactants(smaller ratio)

mol NaCl from limiting reactants :

[tex]\tt \dfrac{6}{1}\times 0.49=2.94[/tex]

mass NaCl

[tex]\tt mol\times MW=2.94\times 58,44~g/mol=171.81~g[/tex]

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