Which of the following is part of the solution to the trigonometric inequality 3-tan(x)>=4-2tan(x) over the interval 0<= x. <=2pi radians?
a.x= pi/6
b. x=pi/3
c.x=2pi/3
d. x=5pi/6

Respuesta :

Answer:

b) pi/3

Step-by-step explanation:

Edge 2020

The one of the solution of  trigonometric inequality

[tex]3-tan(x) \geq 4-2tan(x)[/tex]  over the interval [tex]0 \leq x \leq 2\pi[/tex] radians is . [tex]x = \frac{\pi }{3}[/tex]

What is trigonometric inequality?

An inequality of the standard form R(x) > 0 (or < 0) that consists of 1 or a few trigonometric functions of the variable arc x is a trigonometric inequality. Finding a solution to the inequality means determining the values of the variable arc x whose trigonometric functions make the inequality true.

According to the question

The trigonometric inequality is :

[tex]3-tan(x) \geq 4-2tan(x)[/tex]  

over the interval [tex]0 \leq x \leq 2\pi[/tex] radians

Now ,

Solving the trigonometric inequality

[tex]3-tan(x) \geq 4-2tan(x)[/tex]  

[tex]2tan(x) - tan(x) \geq 4 - 3[/tex]

[tex]tan(x)\geq 1[/tex]

we know that

tan(45°) = 1

Therefore , substituting the value of tan(45°) at place of  1

[tex]tan(x)\geq tan(45)[/tex]

comparing both side

[tex]x\geq 45[/tex]

x in radian

[tex]x \geq \frac{\pi }{4}[/tex]

but the interval of x  is 0 ≤ x ≤ 2[tex]\pi[/tex]  

Now,

[tex]tan (x)[/tex] will be greater than 1 only when x lies between 45° or  [tex]\frac{\pi }{4}[/tex]  and 90 or π .

Hence, the one of the solution of  trigonometric inequality

[tex]3-tan(x) \geq 4-2tan(x)[/tex]  over the interval [tex]0 \leq x \leq 2\pi[/tex] radians is . [tex]x = \frac{\pi }{3}[/tex]

To know more about  trigonometric inequality here:

https://brainly.com/question/20719017

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