Determine if line KM and line ST are ॥, ⊥, or neither: K(-5,1) , M(-2,-8), and S(12,14), T(20,-10) Parallel Perpendicular or neither. i will mark you the brainlest if you answer in under 10 minutes of working

Respuesta :

Answer:

The lines are parallel i.e. KM || ST

Step-by-step explanation:

Given

K(-5,1) , M(-2,-8), and S(12,14), T(20,-10)

In order to find if the lines are parallel, perpendicular or neither slope will be used.

The slope of any line which passes from two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by the formula

[tex]m = \frac{y_2-y_1}{x_2-x_1}[/tex]

If two lines are parallel their slope is equal. If two lines are perpendicular the product of their slope is equal to -1

So, first slopes of both lines will be calculated.

Let m1 be the slope of KM

and

m2 be the slope of ST

In case of KM:

[tex](x_1,y_1) = (-5,1)\\(x_2,y_2) = (-2,-8)[/tex]

Putting the values in the formula for slope

[tex]m_1 = \frac{-8-1}{-2-(-5)}\\m_1 = \frac{-9}{-2+5}\\= \frac{-9}{3}\\= -3[/tex]

In case of ST:

[tex](x_1,y_1) = (12,14)\\(x_2,y_2) = (20,-10)[/tex]

Putting the values in the formula for slope

[tex]m_2 = \frac{-10-14}{20-12}\\= \frac{-24}{8}\\= -3[/tex]

As we can see that slope of both lines KM and ST are equal

i.e. m1 = m2 = -3

Hence,

The lines are parallel i.e. KM || ST

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