The pressure inside a sealed container of nitrous oxide (N,O) at the dentist's office is 8.5 kPa. If the
original temperature of 295 K is increased to 305 K, what will be the new pressure?

Respuesta :

Answer:

8.8kPa

Explanation:

Given parameters:

Initial pressure  = 8.5kPa

Initial temperature  = 295k

New temperature  = 305k

Unknown:

New pressure  = ?

Solution:

To solve this problem, we have to apply the combined gas law when the volume is constant;

in this instant, when the volume is constant, the pressure of a given mass of gas varies directly with the absolute temperature.

          [tex]\frac{P_{1} }{T_{1} }[/tex]   = [tex]\frac{P_{2} }{T_{2} }[/tex]  

P and T are pressure and temperature

1 and 2 are initial and final states

  Insert the parameters and solve;

       [tex]\frac{8.5}{295}[/tex]   = [tex]\frac{P_{2} }{305}[/tex]  

      P₂  = 8.8kPa

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