Is there a series of rigid transformations that could map ΔQRS to ΔABC? If so, which transformations could be used?

No, ΔQRS and ΔABC are congruent but ΔQRS cannot be mapped to ΔABC using a series rigid transformations.
No, ΔQRS and ΔABC are not congruent.
Yes, ΔQRS can be translated so that R is mapped to B and then rotated so that S is mapped to C.
Yes, ΔQRS can be translated so that Q is mapped to A and then reflected across the line containing QS.

Respuesta :

Answer:

It’s D

Step-by-step explanation:

The two triangles are congruent based on congruency postulates, and

therefore, ΔQRS can be mapped to ΔABC.

Correct response;

  • Yes, ΔQRS can be translated so that Q is mapped to A and then reflected across the line containing [tex]\overline{QS}[/tex]

How to determine the rigid transformations that could used to map the congruent triangles?

The possible dimensions given triangles obtained from a similar question online are;

[tex]\overline{QR}[/tex] = [tex]\overline{AB}[/tex] = 16 cm

[tex]\overline{RS}[/tex] = [tex]\overline{BC}[/tex] = 24 cm

∠QRS = ∠ABC = 90°

Therefore;

ΔQRS is congruent to ΔABC by Side-Angle-Side congruency postulate.

Given that the two triangles are congruent, ΔQRS can be mapped to

ΔABS by a series of rigid transformation that involves;

A translation of the point Q to the point A, followed by a reflection across the line containing [tex]\mathbf{\overline{QS}}[/tex] maps the ΔQRS to ΔABC.

The correct option is therefore;

Yes, ΔQRS can be translated so that Q is mapped to A and then reflected across the line containing [tex]\underline{\overline{QS} .}[/tex]

Learn more about rigid transformations here:

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