Find two consecutive odd numbers such that the sum of the larger number and twice the smaller number is 27 less than four times the smaller number.

Respuesta :

Answer:

29

31

Step-by-step explanation:

Let the larger number be 2x + 3      when you add 3 to an even number (2x) you get an odd number

Let the smaller number be 2x + 1     when you add 1 to an even number you get an odd number.

2x + 3 + 2*(2x + 1) = 4(2x + 1) - 27

2x + 3 + 4x + 2 = 8x + 4 - 27

6x + 5 = 8x - 23

28 = 2x

x = 14

2*14 + 1 = 29

2*14 + 3 = 31

Check.

31 + 2*29 = 31 + 58 = 89

4*29 - 27

116 - 27

89

The answers check

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