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Students set up an experiment with a small block on a ramp. The block of mass M=3.0 kg is released from rest at the top of the curved ramp. The length of the ramp as measured along the curve is L=3.0 m, and the height is h=1.5 m, as shown. There is negligible friction between the small block and the ramp.

The speed of the block at the bottom of the ramp is most nearly
A. 0
B. 5.5 m/s
C. 7.7 m/s
D. 9.5 m/s
E. 13 m/s

Students set up an experiment with a small block on a ramp The block of mass M30 kg is released from rest at the top of the curved ramp The length of the ramp a class=

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Answer:

Explanation:

potential energy will be converted into kinetic energy

P E = mgh

K E = 1/2 m V²

mgh  =  1/2 m V²

V² = 2gh

V= √ 2gh

√ (2 x 9.8  x 1.5)

= 5.5 m /s

pstnonsonjoku

The speed of the block at the bottom of the ramp is 5.5 m/s.

Looking at the image we can see that;

Potential energy = mgh

Kinetic energy =1/2 mv^2

As the object is falling, its potential energy at the top of the ramp where it is at rest is converted to kinetic energy.

Where;

h = 1.5 m

g = 10 m/s^2

v = ?

mgh = 1/2 mv^2

v = [tex]\sqrt{2gh}[/tex]

v= [tex]\sqrt{2 * 10* 1.5}[/tex]

v =5.5 m/s

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