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A basketball player had 2 free-throws at the basket missed out of 25 free-throws in all.

What percent of free-throws were missed?

Respuesta :

jenpalacio85

Answer:

92%

Step-by-step explanation:

p/w=%/100

Since he only missed two you do 25-2 which equals 23

23/25=%/100

23×100=2,300

2,300÷25=92

Hope this helps! Plz mark as brainliest! :)

shamusmcgraw

Answer:

92%

Step-by-step explanation:

p/w=%/100

Since he only missed two you do 25-2 which equals 23

23/25=%/100

23×100=2,300

2,300÷25=92

Hope this helps! Plz mark as brainliest! :)

Step-by-step explanation:

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