A worker has to move a 800 kg crate. He pulls with a force of 5,700 N and
the Force of Friction working against him is 900 N. What is the acceleration
of the crate?

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LammettHash LammettHash · Answer 1 · 2020-11-04T21:48:05+01:00

There is a net force being applied in the direction that the crate is being pulled of 5700 N - 900 N = 4800 N.

By Newton's second law, this net force is proportional to the crate's acceleration a by a factor of the crate's mass:

4800 N = (800 kg) a

a = (4800 N) / (800 kg)

a = 6 m/s²

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okpalawalter8 okpalawalter8 · Answer 2 · 2021-10-29T12:18:48+02:00

we have that from the Question, it can be said that the acceleration of the crate is

a=6m/s^2

From the Question we are told

A worker has to move a 800 kg crate. He pulls with a force of 5,700 N and the Force of Friction working against him is 900 N.

What is the acceleration of the crate?

Generally the equation for acceleration is mathematically given as

[tex]a=\frac{F}{m}\\\\Therefore\\\\a=\frac{F}{m}\\\\a=\frac{5700-900}{800}\\\\[/tex]

a=6m/s^2

Therefore

the acceleration of the crate is

a=6m/s^2

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