Respuesta :

hnori22003

[tex] \cos(2x) + {sin}^{2}(x) = [/tex]

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[tex] \cos(2x) = {cos}^{2}(x) - {sin}^{2}(x) [/tex]

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[tex] {cos}^{2}(x) - {sin}^{2}(x) + {sin}^{2}(x) = \\ [/tex]

[tex] {cos}^{2}(x) = 1 - {sin}^{2}(x) [/tex]

Thus the correct answer is (( A )) .

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msm555

cos2x + sin^2x =1-2sin²x+sin²x=1-sin²x

so

your answer is:A. 1 - sin^2x

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