The motor is lifting the 6 kg box at a constant velocity. How much work is done on the
box to lift it 2 m? (Assume no resistance from the pulley.)

Respuesta :

Answer:

117.6 J

Explanation:

We use the formula for work as force times the distance. The force applied to lift the box at constant speed must equal the weight of the box:

F = m * g = 6 * 9.8 N = 58.8 N

Then we multiply this times the distance the box is moved:

Work = F * d = 58.8 * 2  J = 117.6 J

The work done will be "117.6 J".

Work done:

According to the question,

Mass of box, m = 6 kg

Displacement, d = 2 m

Acceleration due to gravity, g = 9.8 N

We know the formula,

→ Force = Mass × Acceleration due to gravity

or,

→ F = m × g

By substituting the values, we get

      [tex]= 6\times 9.8[/tex]

      [tex]= 58.8[/tex] N

hence,

The work done will be:

→ Work = Force × Displacement

or,

→ W = F × d

By substituting the values,

       = [tex]58.8\times 2[/tex]

       = [tex]117.6[/tex] J

Thus the above response is correct.

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