A translation is a rigid transformation where the location of a figure is changed while the dimensions and orientation of the figure remains the same
The translation that will change ABCD to figure A'B'C'D' is 2 units left and 4 units up
The reason the above translation is the correct is given as follows:
Given:
The coordinates of the change A(1, -3), Â B(1, -1), C(3, 1), and D(3, -3)
The coordinates of figure A'B'C'D' are A'(-1, 1), B'(-1, 3), C'(1, 5)), D'(1, 1)
Solution:
Finding the difference in the x and y-values gives;
[tex]\begin{array}{|c|c|c|c| }&\Delta x& \Delta y& Transformation\\A' - A&-1 -1 = -2&1 - (-3) = 4&T_{(-2, \, 4)}\\B' - B&-1 - 1 = -2&3 - (-1) = 4&T_{(-2, \, 4)}\\C' - C&1 - 3 = -2&5 - 1 = 4&T_{(-2, \, 4)}\\D' - D&1 - 3 = -2&1 - (-3) = 4&T_{(-2, \, 4)}\end{array}\right][/tex]
Therefore, the common transformation of the points of ABCD to give A'B'C'D' is [tex]T_{(-2, \ 4)}[/tex], which is 2 units left and 4 units up
Learn more about rigid transformations here:
https://brainly.com/question/5922529
