A tennis ball was thrown straight up with initial velocity of 22.5 m/s. How high does the ball rise
taking into consideration that upward acceleration due to gravity is -9.81m/s ?

Respuesta :

Answer:

[tex]h_m=25.8\ m[/tex]

Explanation:

Vertical Launch Upwards

In a vertical launch upwards, an object is launched vertically up without taking into consideration friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

[tex]\displaystyle h_m=\frac{v_o^2}{2g}[/tex]

The tennis ball was thrown straight up with a speed of v0=22.5 m/s. The acceleration of gravity is g=9.81\ m/s^2, thus:

[tex]\displaystyle h_m=\frac{22.5^2}{2\cdot 9.81}[/tex]

[tex]\mathbf{h_m=25.8\ m}[/tex]

Answer:

4.6 s

Explanation:

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