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An aerosol spray can of deodorant with a volume of 360 mL contains 3.2 g of propane gas (C3H8) as propellant. What is the pressure in the can at 20 ∘C?

Respuesta :

Answer:

P = 0.004 atm (Approx)

Explanation:

Given:

Volume V = 360 ml

Mass m = 3.2 g

Temperature T = 20 degree C = 20 + 273 = 293 K

Find:

Pressure P

Computation:

Moles of propane = 3.2 / 44.1 = 0.072

P = nRT / V

P = (0.072)(0.08206)(293) / 360

P = 0.004 atm (Approx)

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