Answer:
Density, [tex]d=2.03\ g/cm^3[/tex]
Explanation:
Given that,
Mass of the sample, m = 55.6 grams
The sample is submerged in water and 27.3 mL of water is displaced.
We need to find the density of a sample of an small asteroid. It is equal to the mass of the object per unit volume.
1 mL = 1 cm³
So,
[tex]d=\dfrac{55.6\ g}{27.3\ cm^3}\\\\d=2.03\ g/cm^3[/tex]
So, the density of the sample is [tex]2.03\ g/cm^3[/tex].
