Respuesta :

anfabba15

Answer:

2 L is the new volume

Explanation:

We can apply the Ideal Gases Law to solve the problem.

At STP, we kwow that 1 mol of gas occupy a volume of 22.4 L

Then, how many moles do we have in 1 L?

Let's do it by a rule of three:

(1L . 1 mol) / 22.4L = 0.0446 moles

These moles are at 1 atm and 273 K of temperature, so let's change our conditions.

P . V = n . R .T

1 atm . V = 0.0446 mol . 0.082 L.atm/mol K . 546 K

V = 2 L

If we pay attention, we can notice that, if we double temperature, we double the volume.

dsdrajlin

A gas occupies 1.0 L at STP. If the temperature is raised to 546 K, the volume increases to 2.0 L.

The volume of a sample of a gas is 1.0 L (V₁) at standard temperature (T₁ = 273.15 K) and standard pressure (1 atm).

If the pressure remains constant and the temperature is raised to 546 K (T₂), we can calculate the new volume (V₂) using Charles' law.

[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2} \\\\V_2 = \frac{V_1 \times T_2 }{T_1} = \frac{1.0 L \times 546K }{273.15K} = 2.0 L[/tex]

A gas occupies 1.0 L at STP. If the temperature is raised to 546 K, the volume increases to 2.0 L.

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