Answer:
The impulse it received from the person tossing the stone is 2.58 N.s
Explanation:
Given;
mass of the stone, m = 0.28 kg
height risen by the stone in air, h = 4.3 meters
Time taken for the stone to reach 4.3 meters is given by;
[tex]t = \sqrt{\frac{2h}{g} }\\\\t = \sqrt{\frac{2*4.3}{9.8}}\\\\t = 0.94 \ s[/tex]
Impulse is given as;
J = Ft
where;
force applied on the stone due to its weight
J = (mg)t
J = (0.28 x 9.8)(0.94)
J = 2.58 N.s
Therefore, the impulse it received from the person tossing the stone is 2.58 N.s
