Answer:
3.07mg of BaSO₄ is the mass that can dissolve in 340.0mL of solution
Explanation:
The Ksp value of BaSO₄ is 1.5x10⁻⁹
The dissolution of BaSO₄ in water follows the equation:
BaSO₄(s) ⇄ Ba²⁺(aq) + SO₄²⁻(aq)
And ksp is defined as:
Ksp = 1.5x10⁻⁹ = [Ba²⁺] [SO₄²⁻]
As both Ba²⁺ and SO₄²⁻ ions comes from the same salt, the concentration of both ions = The maximum concentration that can be dissolved of BaSO₄ is X:
1.5x10⁻⁹ = [Ba²⁺] [SO₄²⁻]
1.5x10⁻⁹ = [X] [X]
1.5x10⁻⁹ = X²
X =
3.87x10⁻⁵M = [BaSO₄]
In 340mL = 0.340L, the moles of BaSO₄ are:
0.340L * (3.87x10⁻⁵ moles / L) = 1.317x10⁻⁵ moles of BaSO₄
To convert these moles to the mass in grams we need to use molar mass of BaSO₄ -233.38g/mol-:
1.317x10⁻⁵ moles of BaSO₄ * (233.38g / mol) = 3.07x10⁻³g =
