Complete question is;
Suppose that the distance of fly balls hit to the outfield (in baseball) is normally distributed with a mean of 244 feet and a standard deviation of 44 feet. Let X = distance in feet for a fly ball.
If one fly ball is randomly chosen from this distribution, what is the probability that this ball traveled fewer than 184 feet? (Round your answer to four decimal places.)
Answer:
0.1814
Step-by-step explanation:
We are given;
Mean; μ = 244
Standard deviation; σ = 44
Test score; x' = 204
z-score = (x' - μ)/σ
z = (204 - 244)/44
z = -0.91
Thus, probability that X travelled fewer than 184 ft is;
P(X < 184) = P(Z = -0.91)
From z-distribution table attached, P = 0.18141
Thus; P(X < 184) ≈ 0.1814
