Answer:
259.456 J
Explanation:
Given that,
Work done on the system = 166 cal
The systam releases 954 J of thermal energy to its surroundings
We need to find the change in internal energy. It can be given by using the first law of thermodynamics as follows :
[tex]\Delta U=Q-W[/tex]
W = 166 cal = 694.544 (1cal = 4.184 J)
[tex]\Delta U=954-694.544\\\\=259.456\ J[/tex]
So, the change in internal energy of the system is 259.456 J.
