Answer:
The frictional force is [tex]F_f = 1.75 \ N[/tex]
Explanation:
From the question we are told that
The coefficient of kinetic force is μk = 0.35
The normal force felt by the puck is [tex]F_N = 5 \ N[/tex]
Generally the frictional force that acts on the puck is mathematically represented as
[tex]F_f = \mu_k * F_N[/tex]
=> [tex]F_f = 0.35 * 5[/tex]
=> [tex]F_f = 1.75 \ N[/tex]
