Given :
In a pet competition, it costs $42 to enter a cat and $31 to enter a dog. A total of 149 pets were entered and $5,026 was made.
To Find :
How many dogs were their.
Solution :
Let, number of cats and dog are c and d.
c + d = 149 ....1)
42c + 31d = 5026 ...2)
Putting value of c in equation 2, we get :
42( 149 - d ) + 31d = 5026
6258 - 42d + 31d = 5026
11d = 6258 - 5026
11d = 1232
d = 112
Therefore, number of dogs in competition are 112.
Hence, this is the required solution.
