Answer:
56.17% is percent composition of Sb in the molecule
Explanation:
Percent composition is the percent in mass of each element present in a particular molecule.
In SbF₅, there is 1 mole of Antimony -Molar mass: 121.76g- per 5 moles of fluorine -Molar mass: 19g/mol-. In a basis of 1 mole, the mass of Sb and F is:
Mass Sb:
1mol * (121.76g/mol) = 121.76g
Mass F:
1 mol SbF₅ = 5 moles F * (19g / mol) = 95g
Total mass:
121.76g + 95g = 216.76g
And percent composition of Sb:
121.76g / 216.76g * 100 =
