g Suppose the investigators had made a rough guess of 0.14 for the value of the sample standard deviation, s, before collecting data. What sample size would be necessary to obtain an interval width of 0.04 from a confidence level of 99% for a two-sided confidence interval

Respuesta :

Answer:

The sample size is   [tex]n =326 [/tex]

Step-by-step explanation:

From the question we are told that

  The rough estimate of the standard deviation is  [tex]\sigma = 0.14[/tex]

   The interval width is  [tex]w = 0.04[/tex]

   

Generally the margin of error is mathematically represented as

          [tex]E = \frac{w}{2}[/tex]

=>       [tex]E = \frac{0.04}{2}[/tex]

=>       [tex]E = 0.02[/tex]

From the question we are told the confidence level is   99% , hence the level of significance is    

      [tex]\alpha = (100 - 99 ) \%[/tex]

=>   [tex]\alpha = 0.01[/tex]

Generally from the normal distribution table the critical value  of  [tex]\frac{\alpha }{2}[/tex] is  

   [tex]Z_{\frac{\alpha }{2} } =  2.58[/tex]

Generally the sample size is mathematically represented as

    [tex]n = [\frac{Z_{\frac{\alpha }{2} } *  \sigma }{E} ] ^2[/tex]

=>   [tex]n = [\frac{ 2.58 *  0.14 }{0.02} ] ^2[/tex]

=>   [tex]n =326 [/tex]

Q&A Education