Answer:
1.75 mol CO₂
Explanation:
Step 1: Given data
Moles of calcium carbonate: 1.75 mol
Step 2: Write the balanced decomposition reaction
CaCO₃ ⇒ CaO + CO₂
Step 3: Calculate the moles of carbon dioxide produced from 1.75 moles of calcium carbonate
The molar ratio of CaCO₃ to CO₂ is 1:1. The moles of CO₂ produced are:
1.75 mol CaCO₃ × (1mol CO₂/1 mol CaCO₃) = 1.75 mol CO₂
A decomposition is a reaction in which a compound or a molecule splits in two or more compounds.
The decomposition reaction for calcium carbonate, CaCO₃ is:
CaCO₃ ⇒ CaO + CO₂
The moles of carbon dioxide (CO₂), produced in the decomposition reaction will be 1.75 mol .
This can be explained as:
CaCO₃ ⇒ CaO + CO₂
[tex]\text{1.75 mol}\;\text{CaCO}_{3} \times \dfrac{\text{1 mol}\;\text{CO}_{2} }{\text {1 mol}\;\text{CaCO}_{3} }[/tex]
= 1.75 mol CO₂
Therefore, the moles of CO₂ generated by the decomposition of calcium carbonate is 1.75 mol.
To learn more about moles and decomposition reactions follow the link:
https://brainly.com/question/1264655
