Answer:
6.68kJ
Explanation:
In a neutralization reaction (Of an acid HX and a base as NaOH), some heat is released:
NaOH + HX → H₂O + NaX + ΔH
Where ΔH is heat released.
Now, to find change in heat in a coffee calorimeter you must use the equation:
Q = m×C×ΔT + S×ΔT
Where Q is heat,
m is mass of solution: 100g (50mL of both solutions assuming density of 1g/mL)
C is specific heat of the solution: 4.184J/g°C
ΔT is change in temperature (35.7°C - 20.5°C = 15.2°C)
And S is calorimeter constant: 21.0J/°C
Replacing:
Q = m×C×ΔT + S×ΔT
Q = 100g×4.184J/g°C×15.2°C + 21.0J/°C×15.2°C
Q = 6679J is the heat evolved in the reaction:
