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A refrigerator requires 10 J of work and exhausts 65 J of heat per cycle. What is the refrigerator's coefficient of performance

Respuesta :

onyebuchinnaji

Answer:

The refrigerator's coefficient of performance is 5.5.

Explanation:

Given;

work required, W = 10 J

heat exhausts per cycle, Q = 65 J

determine the energy removed from the cold reservoir, which is inside the refrigerator;

[tex]W_{in} = Q_H - Q_C[/tex]

10 = 65 - Qc

Qc = 65 - 10

Qc = 55

The coefficient of performance of heat pump used for cooling id given by;

[tex]COP = \frac{Q_C}{W_{in}}\\\\COP = \frac{55}{10}\\\\ COP = 5.5[/tex]

Therefore, the refrigerator's coefficient of performance is 5.5.

snehashish65

The required value of coefficient of performance of refrigerator is 5.5 .

Given data:

The amount of work input to the refrigerator is, W = 10 J.

The heat output from the refrigerator is, Q = 65 J.

The ratio of heat removed from the system to the work done to remove the heat, is known as the coefficient of performance of refrigerator. Then, the expression is given as,

COP = Q'/W

Here, Q ' is the amount of heat removed from the system. And its value is,

W = Q - Q'

Q' = Q - W

Then the COP is,

COP = (Q -W)/W

COP = 55/10

COP = 5.5

Thus, we can conclude that the required value of coefficient of performance of refrigerator is 5.5 .

Learn more about the coefficient of performance of refrigerator here:

https://brainly.com/question/13326702

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