Answer:
The angle is 84.26⁰
Explanation:
The angle the axis of a polarizing filter need to make with the direction of polarized light is given by;
I = I₀Cos²θ
where;
I is the intensity of the polarized light transmitted from the polarizer
I₀ is the intensity of the polarized light incident on the polarizer
Given;
I₀ = 1.00 kW/m² = 1000 W/m²
I = 10 W/m²
[tex]Cos^2 \theta = \frac{I}{I_o}\\\\Cos \theta = \sqrt{\frac{I}{I_o}}\\\\\theta = Cos^{-1}( \sqrt{\frac{I}{I_o}})\\\\\theta = Cos^{-1}( \sqrt{\frac{10}{1000}})\\\\\theta = 84.26^0[/tex]
Therefore, the angle is 84.26⁰
