Answer:
The probability of selecting the green ball from urn III is ²/₃
Step-by-step explanation:
Given;
total number of balls in urn I = 10
number of green balls in urn I , = 2
total number of balls in urn II = 10
number of green balls in urn II , = 2
total number of balls in urn III = 10
number of green balls in urn II , = 8
[tex]P = \frac{\frac{8}{10} }{\frac{2}{10} + \frac{2}{10}+ \frac{8}{10}}\\\\P = \frac{\frac{8}{10} }{\frac{12}{10} }\\\\P = \frac{8}{10} *\frac{10}{12} \\\\P = \frac{8}{12}\\\\ P = \frac{2}{3}[/tex]
Therefore, the probability of selecting the green ball from urn III is ²/₃
