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A cylinder of oxygen gas has a volume of 10.0 liters at 7.66 atm and 27.0oC. The cylinder is heated until the pressure is 428 kPa and the volume reaches 30.0 liters. What is the new temperature of the cylinder?

Respuesta :

Answer:

Explanation:

428 x 10³ Pa = 4.28 x 10⁵ Pa = 4.28 atm

We shall use the gas equation

P₁V₁ / T₁ = P₂V₂ / T₂

7.66  x 10 / ( 273 + 27 ) = 4.28 x 30 / T₂

.255 = 128.4 / T₂

T₂ = 503.53

= 503.53 - 273 = 230.53⁰C .

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